How far did the car travel in the entire 4 hours? ![]() A car travels at an average of 50 miles per hour for 212 hours and then travels at a speed of 70 miles per hour for 112 hours. Give that the person would have covered (x + 20) km if travelled at 14 km/hr What is the actual distance travelled by him?Īssume that the person would have covered x km if travelled at 10 km/hr If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. ⇒ Distance between his house and office =12/2=6 kmĥ. If a car covers a certain distance at x kmph and an equal distance at y kmph,the average speed of the whole journey = 2xy/(x+y) kmph If he takes 5 hours in going and coming, what is the distance between his house and office? A man goes to his office from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. Hence new time = 7/6 of usual time Hence, 7/6 of usual time – usual time = 12 minutes => 1/6 of usual time = 12 minutes => usual time = 12 x 6 = 72 minutes = 1 hour 12 minutesĤ. New speed = 6/7 of usual speed Speed and time are inversely proportional. What is the usual time taken by him to cover that distance? Walking 6/7 th of his usual speed, a man is 12 minutes too late. 5 kmph (because they walk in the same direction)ģ. What time will they take to be 8.5 km apart? ![]() Two boys starts from the same place walking at the rate of 5 kmph and 5.5 kmph respectively in the same direction. Time = 5 minutes = 5 x 60 seconds = 300 seconds A person crosses a 600 m long street in 5 minutes. If the ratio of the speeds of A and B is a : b, then the ratio of the times taken by them to cover the same distance is 1/a:1/b or b : aġ.Speed and time are inversely proportional (when distance is constant) ⇒ Speed ∝ 1/Time (when distance is constant).If a car covers a certain distance at x kmph and an equal distance at y kmph, the average speed of the whole journey = 2xy/(x+y) kmph.To convert Meters per Second(m/s) to Kilometers per Hour(km/hr) x m/s=(x×18)/5 km/hr.To convert Kilometers per Hour(km/hr) to Meters per Second(m/s) x km/hr=(x×5)/18m/s. ![]() This chapter will form the basis of further concept of relative speed which is used in train and boat problems. In this module we will deal with basic concepts of time and distance, speed, average speed, conversion from km/h to m/s and vice versa.
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